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(F)=2F^2-6F-1
We move all terms to the left:
(F)-(2F^2-6F-1)=0
We get rid of parentheses
-2F^2+F+6F+1=0
We add all the numbers together, and all the variables
-2F^2+7F+1=0
a = -2; b = 7; c = +1;
Δ = b2-4ac
Δ = 72-4·(-2)·1
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$F_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{57}}{2*-2}=\frac{-7-\sqrt{57}}{-4} $$F_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{57}}{2*-2}=\frac{-7+\sqrt{57}}{-4} $
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